0=16x-0.01x^2-900

Solution for 0=16x-0.01x^2-900 equation:

0=16x-0.01x^2-900

We move all terms to the left:

0-(16x-0.01x^2-900)=0

We add all the numbers together, and all the variables

-(16x-0.01x^2-900)=0

We get rid of parentheses

0.01x^2-16x+900=0

a = 0.01; b = -16; c = +900;
Δ = b2-4ac
Δ = -162-4·0.01·900
Δ = 220
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{220}=\sqrt{4*55}=\sqrt{4}*\sqrt{55}=2\sqrt{55}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-2\sqrt{55}}{2*0.01}=\frac{16-2\sqrt{55}}{0.02}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+2\sqrt{55}}{2*0.01}=\frac{16+2\sqrt{55}}{0.02}
$